Root Test for Series: Statement, Solved Examples

Cauchy’s Root test for series is used to test the convergence or divergence of an infinite series. It states that if limn→∞ an1/n is less than 1 then the series ∑an converges and if the limit is greater than 1 then the series diverges. In this article, we will study Cauchy root test of a series with examples.

Root Test Rule

Statement: Let $\displaystyle \sum_{n=1}^\infty a_n$ be a series of positive real numbers. Suppose that

R = $\lim\limits_{n \to \infty} (a_n)^{1/n}$.

Then by root test we have the following.

  • If R<1, then the series ∑an converges.
  • If R>1, then ∑an diverges.
  • If R=1, the root test is indecisive.

Root Test Solved Examples

$\boxed{\color{blue}\textbf{Q}1:}$ Test the convergence of $1+\dfrac{1}{2^2}+\dfrac{1}{3^3}+\cdots$.

The given series = $\displaystyle \sum_{n=1}^\infty \dfrac{1}{n^n}$

Here, $a_n=\dfrac{1}{n^n}$.

Therefore,

R = limn→∞ $(a_n)^{1/n}$

= limn→∞ $\left( \dfrac{1}{n^n} \right)^n$

= limn→∞ $\dfrac{1}{n}$

= 0.

Since the limit R<1, the given series converges by root test.

$\boxed{\color{blue}\textbf{Q}2:}$ Test the convergence of the series $\displaystyle \sum_{n=1}^\infty a_n$ where an = $\dfrac{(1+n)^{n^2}}{n^{n^2}}$.

R = limn→∞ $(a_n)^{1/n}$

= limn→∞ $\left( \dfrac{(1+n)^{n^2}}{n^{n^2}} \right)^n$

= limn→∞ $\left( \dfrac{n+1}{n} \right)^n$

= limn→∞ $\left( 1+\dfrac{1}{n} \right)^n$

= e >1 as the value of e lies between 2 and 3.

Since the limit R>1, the given series diverges by root test.

Related Articles:

Test the convergence of the following series:

  1. $\displaystyle \sum_{n=1}^\infty \dfrac{n^{n^2}}{(1+n)^{n^2}}$
  2. $\dfrac{1}{2}+\dfrac{1}{3^2}+\dfrac{1}{4^3}+\cdots$

FAQs

Q1: State root test for series.

Answer: Let ∑an be a series of positive terms and let R = limn→∞ (an)1/n. The root test states that the series ∑an converges if R<1, and ∑an diverges if R>1.

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